Answers to Practice Exam One

June 15, 2008

Here are answers to the practice exam I gave you on the last day of class.  Let me know if you think I made a mistake–I’m human, after all!

1. 3       2. 2       3. 2       4. 1       5. 2       6. 2       7. 4

8. 4       9. 1     10. 3     11. 3     12. 1     13. 4     14. 3

15. 3     16. 2     17. 4     18. 2     19. 2     20. 1     21. 2

22. 2     23. 4     24. 3     25. 2     26. 3     27. 4     28. 3

Now for the free-response questions:

29.  (x + 2)↑2 + (y – 4)↑2 = 2.25
30.  perimeter = 100
31.  perimeter = 30
32.  3 √2
33.  12
34.  (1, 0)
35.  y = -x + 1
36.  36
37.  27 π
38.  For this proof, show that triangles PAL and REG are similar (they are congruent, actually), then state that corresponding sides of similar triangles are proportional, then cross-multiply to convert the proportion into the given multiplication.

You probably noticed that I had to fudge a couple of the mathematical figures, due to the limitations of this weblog (and my limitations in figuring out how to overcome them!)

Other notes and comments:

  • The proof that you will have to do for your exam is, I think, easier than the one shown here.
  • This practice test did not include andy coordinate geometry proofs, which you need to be able to do.
  • You also need to know how to find the area of a regular polygon.
  • You must be able to do constructions using compass and straightedge.  Refer to the packet I gave you in class last week.
  • If I remember correctly, much of the class struggled with the angles in circles.  Might I politely suggest that would be a topic worth reviewing?

As demonstrated in this practice exam, knowledge of 30-60-90 triangles and 45-45-90 triangles and the ratio of their sides is beneficial, as is the Pythagorean Theorem. This practice exam did not test any trig.  We probably will.

Review Session:  Monday a.m. from 9 until about 11:30.  You do not have to be there the entire time, but you will need a pass to get in.

Exam:  Monday afternoon at 12:45 in the gym.  Be there or be a quadrilateral that is both a rhombus and a rectangle!